Solving x = T(x): the same idea on four unknowns
Click or drag on the plot to choose the starting point. Keyboard: space or → to step, ← to go back, R to reset.
Error |xk − x*| for every method from the same start
Predict. There is no discount factor here, so what makes Picard converge? Lengthen the horizon: why does the error climb before it falls, and how does that differ from Newton?
Iterates: angle θ(t) as one point in a space of curves
Solution of the discretized equation
Current iterate, older iterates paler
Largest error along the curve
Picard
Newton
Predict. With a one-year horizon and no terminal value, what happens to the water by December? As γ goes from 0.8 to 0.99, how many more years does value iteration need, and how many more Newton steps?
Value iteration: years to reach v* within 1 $
Policy iteration: Newton steps to reach v*
Years until the greedy policy loses less than 1 k$
Terminal water price implied by v* at 1100 hm³ (the slider last time said 50)
Value of storage on 1 January (M$)
vk = Bk 0, value iteration
Policy iteration iterates
v*
Sup-norm distance to v* (M$)
Value iteration, ‖vk − v*‖
Loss of its greedy policy
Policy iteration